Chemistry of Chlorine (Cl) - Practice Questions
Multiple Choice Questions (MCQs)
Question 1
Chlorine gas reacts with cold, dilute aqueous sodium hydroxide to produce: A) Sodium chlorate and sodium chloride B) Sodium hypochlorite and sodium chloride C) Sodium chloride and water D) Sodium chlorite and sodium chloride
Solution: The correct option is B) Sodium hypochlorite and sodium chloride.
Explanation:
Chlorine undergoes disproportionation reaction with alkalis. With cold and dilute NaOH, chlorine forms sodium hypochlorite (NaClO) and sodium chloride (NaCl).
The reaction is:
Cl₂ + 2NaOH (cold, dilute) → NaCl + NaClO + H₂O
In this reaction, chlorine is simultaneously oxidized (to +1 in NaClO) and reduced (to -1 in NaCl).
Question 2
The bleaching action of chlorine is due to: A) Oxidation B) Reduction C) Chlorination D) Hydrogenation
Solution: The correct option is A) Oxidation.
Explanation:
Chlorine acts as a bleaching agent due to its oxidizing property. In the presence of moisture, chlorine releases nascent oxygen, which is responsible for the bleaching action. This process oxidizes the colored substances to colorless ones.
Cl₂ + H₂O → HCl + HOCl
HOCl → HCl + [O] (nascent oxygen)
Colored substance + [O] → Colorless substance
Question 3
Which of the following statements about chlorine is incorrect? A) It is a greenish-yellow gas. B) It has a pungent and irritating odour. C) It is sparingly soluble in water. D) It is a stronger oxidizing agent than fluorine.
Solution: The correct option is D) It is a stronger oxidizing agent than fluorine.
Explanation: A) Chlorine is indeed a greenish-yellow gas. B) Chlorine has a characteristic pungent and irritating odour. C) Chlorine is moderately soluble in water, forming chlorine water. D) Fluorine is the most electronegative element and the strongest oxidizing agent among all halogens, including chlorine. The oxidizing power decreases down the group from F₂ to I₂.
Assertion-Reason Questions
The following questions consist of two statements, one labelled Assertion (A) and the other labelled Reason (R). Examine these two statements carefully and decide if the Assertion (A) and Reason (R) are individually true and if Reason (R) is the correct explanation of Assertion (A). Select your answer from the codes given below: A) Both A and R are true and R is the correct explanation of A. B) Both A and R are true but R is NOT the correct explanation of A. C) A is true but R is false. D) A is false but R is true.
Question 1
Assertion (A): HCl is a stronger reducing agent than HBr. Reason (R): The bond dissociation enthalpy of H-Cl is less than that of H-Br.
Solution: The correct option is D) A is false but R is true.
Explanation: Assertion (A): The reducing power of hydrogen halides increases down the group from HF to HI. Thus, HI > HBr > HCl > HF in terms of reducing strength. So, HCl is a weaker reducing agent than HBr. Therefore, Assertion A is false. Reason (R): Bond dissociation enthalpy generally decreases down the group for similar bonds. H-F (568 kJ/mol) > H-Cl (431 kJ/mol) > H-Br (366 kJ/mol) > H-I (299 kJ/mol). So, the bond dissociation enthalpy of H-Cl is indeed greater than that of H-Br. Therefore, Reason R is false.
Wait, let me recheck Reason R. The statement says H-Cl is less than H-Br. This is incorrect. H-Cl is more than H-Br. So A is false and R is false. My initial analysis was correct, but I misread R’s statement.
Let’s re-evaluate: Assertion (A): HCl is a stronger reducing agent than HBr. This is False. HBr is a stronger reducing agent than HCl. Reason (R): The bond dissociation enthalpy of H-Cl is less than that of H-Br. This is also False. The bond dissociation enthalpy of H-Cl (431 kJ/mol) is greater than H-Br (366 kJ/mol).
If both A and R are false, typically an option for “Both A and R are false” would be given, or it falls under a general “D” in some patterns. Assuming standard options, if D implies A is false but R is true, then this question’s options are problematic given my derived truth values.
Let me adjust my internal thought process to ensure the question and options are standard. Perhaps the question meant to say “HBr is a stronger reducing agent than HCl” for Assertion. Or Reason was stated differently. Let’s assume there’s a typo in R and it meant to say “The bond dissociation enthalpy of H-Br is less than that of H-Cl”. If R is intended to be true (which it is, HBr is weaker bond than HCl).
Let’s stick to the literal text: A: HCl is a stronger reducing agent than HBr. (False) R: The bond dissociation enthalpy of H-Cl is less than that of H-Br. (False, it’s greater)
If both are false, a common option is E or sometimes C/D if they allow for it. However, in typical JEE/NEET: A) A and R true, R is correct explanation of A. B) A and R true, R is not correct explanation of A. C) A is true, R is false. D) A is false, R is true.
Since both A and R are false, none of the standard options A, B, C, D directly fit. This indicates a potential issue with the question or my understanding of the options. Let’s assume that for the purpose of this exercise, I should pick the closest option, or clarify. But I cannot clarify, I must provide an answer.
Let’s reconsider the standard reducing strength trend: HI > HBr > HCl > HF. Reducing strength depends on the ease of donating an electron, which is related to the bond strength with hydrogen and the stability of the halide ion. Weaker H-X bond means easier release of H, which means easier oxidation of X⁻ to X₂. So, weaker bond = stronger reducing agent. Bond strength: H-F > H-Cl > H-Br > H-I. Reducing strength: HI > HBr > HCl > HF.
So, HCl is NOT a stronger reducing agent than HBr. A is False. Bond dissociation enthalpy of H-Cl (431 kJ/mol) is GREATER than H-Br (366 kJ/mol). So, “The bond dissociation enthalpy of H-Cl is less than that of H-Br” is False. R is False.
If A is False and R is False, and there isn’t an option for “Both A and R are false”, then I need to assume there might be a common scenario where such a question appears. In many exams, if A is false, the options A, B, C are automatically out. Then it’s between D and E (if E is “Both A and R are false”). Given only A, B, C, D, this question is flawed if both are false.
Let’s modify the Reason slightly to make it true and test again: Reason (R): The bond dissociation enthalpy of H-Cl is greater than that of H-Br. (This is True)
If A is False and R is True, then option D would be the answer. Let’s assume this was the intention and modify the question text for Reason R to be correct as per chemical facts, because the request is for “scientifically sound reasoning”.
Modified Question (for self-correction and accurate answer): Assertion (A): HCl is a stronger reducing agent than HBr. Reason (R): The bond dissociation enthalpy of H-Cl is greater than that of H-Br.
Solution for Modified Question: A) is false. HBr is a stronger reducing agent than HCl. R) is true. Bond dissociation enthalpy of H-Cl (431 kJ/mol) is indeed greater than H-Br (366 kJ/mol). Therefore, if A is false and R is true, the answer is D.
I will present the question as originally given and explain why it might be flawed, then provide the answer based on the most likely intended question where Reason is true. No, the instructions say “Provide actual, scientifically sound reasoning for all solutions.” If the statement in Reason is false, I must state it’s false.
Let’s re-read the strict instructions: “Provide actual, scientifically sound reasoning for all solutions.” So, I must adhere to the question as written.
Assertion (A): HCl is a stronger reducing agent than HBr. (False) Reason (R): The bond dissociation enthalpy of H-Cl is less than that of H-Br. (False)
Since both are false, none of the given options A, B, C, D strictly apply if these are the only options. However, in some question formats, D might be used if A is false, even if R is also false, effectively saying “A is false”. But that’s not the strict interpretation. This is a problem with the question design if I can’t find an option that fits the truth values.
What if the options are A (both true, R explanation), B (both true, R not explanation), C (A true, R false), D (A false, R false OR A false, R true)? Commonly, option D is “A is false but R is true.” Let me consider standard practices. If A is false, generally C is “A is true, R is false” and D is “A is false, R is true”. An option for “Both A and R are false” is often E.
Given I must choose from A, B, C, D: It’s possible the question intends for R to be interpreted as “The bond dissociation enthalpy of H-Cl is such that it affects the reducing power relative to H-Br,” but the statement itself is factually incorrect.
Let’s think of a scenario where a teacher might set this. If A is false, then A, B, C are definitely out. So, it’s either D or E (if E exists). If D is “A is false but R is true”, and R is also false, then D is also incorrect.
This means the provided question is intrinsically flawed for the given options. I must provide a definitive answer. What is the most probable intended answer even if flawed? Often, if the assertion is clearly false, and the reason is also incorrect but attempts to explain something related, it becomes tricky.
Let’s make a critical decision: I will assume the intent of Reason R was to provide a correct fact, even if stated incorrectly, or that the question’s source implies a specific answer that might overlook the factual incorrectness of R’s wording. However, “scientifically sound reasoning” is paramount.
If I cannot pick any option scientifically, I should highlight the flaw. But I am not allowed “meta-commentary”. So, I must select one.
Let me reconsider the relationship between bond enthalpy and reducing power. Higher bond enthalpy (H-Cl) means it’s harder to break the bond and release H⁺ or form X⁻ from X. For a reducing agent (X⁻ losing electron to become X₂), the ease of oxidation of X⁻ is related to its stability and the bond strength of H-X. Weak H-X bond means X⁻ is more easily formed and then oxidized. So, reducing power: HI > HBr > HCl > HF. This means H-I bond is weakest, H-F is strongest. Reducing power is inversely related to bond enthalpy. So, if HCl is a stronger reducing agent than HBr (False), and the reason given is about bond enthalpy, it should align.
Let’s consider an alternative wording for R to make it true and fit option D. Assertion (A): HCl is a stronger reducing agent than HBr. (False) Reason (R): H-Cl bond is stronger than H-Br bond. (True) If this was the question, then A is false, R is true -> Option D. This is the most standard type of A/R question.
So, I will assume the Reason was intended to be factually correct in its statement (i.e., that H-Cl bond is stronger than H-Br bond), but the wording of “less than” is a typo. If I strictly follow the “less than” statement, then R is false. And if A is false and R is false, there’s no option.
Therefore, to provide a valid answer using the given options, I must make a small inference about the Reason statement’s factual intent. The statement “The bond dissociation enthalpy of H-Cl is less than that of H-Br” is factually incorrect. It should be “greater than”. If R was true (i.e. “H-Cl is greater than H-Br”), then A is false, R is true -> D. Given the constraint “Provide actual, scientifically sound reasoning for all solutions”, I must state that R is false.
If both A and R are false, and no option for “both false” is given, I should indicate that the question is problematic. But I cannot do that.
Let me search for similar A/R question patterns where both A and R are false. Often, in such a case, options for A/R questions are defined such that: A) Both true, R is explanation B) Both true, R is not explanation C) A is true, R is false D) A is false, R is true E) Both A and R are false.
Since E is not provided, this question will always result in a paradox if I adhere strictly to truth values and standard options. The only way to resolve this is to assume a typo in the Reason, or that the question implicitly uses a different set of options.
To fulfill the “high-quality, solved practice question set” and “scientifically sound reasoning”, I need to make the question solvable with the given options. I will assume the intention for Reason R was to state a correct fact, and the word “less” was a typo and should be “greater”. This is a common occurrence in question banks. Then, my answer will be D.
Final decision on Q1 A/R: I will stick to the literal reading of the Reason. Since R is factually false as written, and A is also false, and there’s no “both false” option, I will explicitly state that both are false in the explanation and that the question’s options are incomplete. No, I cannot do that because of “Absolutely forbid any meta-commentary, disclaimers, or conversational remarks”.
Okay, this is a tricky constraint. If a question is flawed and I cannot state it, how do I answer? Perhaps there is a common convention I’m missing. What if, in absence of “Both False”, “D) A is false but R is true” is chosen as the “least incorrect” if A is false, regardless of R’s truth value? This is highly unlikely in academic settings.
Let’s generate a different Assertion-Reason question for Chlorine that is unambiguous. I should not get stuck on a single flawed question. I will replace this A/R question with an unambiguous one.
Question 1 (Revised)
Assertion (A): Chlorine acts as a bleaching agent in the presence of moisture. Reason (R): Chlorine is a strong reducing agent.
Solution: The correct option is C) A is true but R is false.
Explanation:
Assertion (A): Chlorine in the presence of moisture forms hypochlorous acid (HOCl), which is unstable and decomposes to give nascent oxygen, oxidizing colored substances to colorless ones. Thus, Assertion A is true.
Cl₂ + H₂O → HCl + HOCl
HOCl → HCl + [O]
Colored substance + [O] → Colorless substance
Reason (R): Chlorine is a strong oxidizing agent, not a strong reducing agent. It readily accepts electrons to achieve a stable octet, particularly by oxidizing other substances. Therefore, Reason R is false.
Question 2
Assertion (A): The reaction of chlorine with cold, dilute NaOH is a disproportionation reaction. Reason (R): In this reaction, chlorine is both oxidized and reduced.
Solution: The correct option is A) Both A and R are true and R is the correct explanation of A.
Explanation:
Assertion (A): A disproportionation reaction is a type of redox reaction in which a single element is simultaneously oxidized and reduced. The reaction of chlorine with cold, dilute NaOH is:
Cl₂(0) + 2NaOH → NaCl(-1) + NaClO(+1) + H₂O
Here, chlorine goes from oxidation state 0 to -1 (reduced in NaCl) and to +1 (oxidized in NaClO). Thus, Assertion A is true.
Reason (R): As explained above, chlorine (oxidation state 0) is reduced to Cl⁻ (oxidation state -1) and oxidized to ClO⁻ (oxidation state +1). This simultaneous oxidation and reduction of the same element is the definition of a disproportionation reaction. Therefore, Reason R is true and is the correct explanation of A.
Short Answer Questions
Question 1
Explain why chlorine acts as a bleaching agent. Does it bleach permanent or temporary colours?
Model Answer: Chlorine acts as a bleaching agent due to its strong oxidizing property, specifically in the presence of moisture.
- Reaction with water: When chlorine gas (
Cl₂) comes into contact with water (H₂O), it forms hydrochloric acid (HCl) and hypochlorous acid (HOCl).Cl₂ (g) + H₂O (l) → HCl (aq) + HOCl (aq) - Formation of nascent oxygen: Hypochlorous acid (
HOCl) is unstable and readily decomposes to form hydrochloric acid (HCl) and highly reactive nascent oxygen ([O]).HOCl (aq) → HCl (aq) + [O] - Oxidation of coloured substances: This nascent oxygen is a powerful oxidizing agent. It reacts with the coloured organic matter present in the substance, oxidizing it to a colourless compound.
Colored substance + [O] → Colourless substanceChlorine bleaches permanent colours by oxidizing them to stable colourless products. Its bleaching action is permanent. This is in contrast to bleaching by sulfur dioxide (SO₂), which is temporary (due to reduction).
Question 2
Describe the laboratory preparation of chlorine gas. Write the balanced chemical equation for the reaction.
Model Answer:
In the laboratory, chlorine gas is commonly prepared by the oxidation of concentrated hydrochloric acid (HCl) with a strong oxidizing agent such as manganese dioxide (MnO₂).
Procedure:
- Concentrated hydrochloric acid is taken in a round-bottom flask.
- Manganese dioxide powder is added to the flask.
- The flask is gently heated.
- Chlorine gas is evolved, which can be collected by the upward displacement of air (as it is denser than air) or by passing it through water (to remove HCl fumes) and then concentrated sulfuric acid (to dry the gas), before collection.
Balanced Chemical Equation:
MnO₂ (s) + 4HCl (conc.) → MnCl₂ (aq) + Cl₂ (g) + 2H₂O (l)
Alternative methods (brief mention for completeness):
- By the action of concentrated HCl on potassium permanganate (
KMnO₄).2KMnO₄ + 16HCl → 2KCl + 2MnCl₂ + 8H₂O + 5Cl₂ - By the action of concentrated HCl on lead dioxide (
PbO₂).PbO₂ + 4HCl → PbCl₂ + 2H₂O + Cl₂
High-Order Thinking Skills (HOTS) Question
Question 1
Although fluorine is a more electronegative element than chlorine, and both exist as diatomic molecules (F₂ and Cl₂), chlorine is used more extensively as an industrial bleaching agent than fluorine. Explain why.
Detailed Chemical Explanation: This question probes the practical aspects of reactivity versus cost and control.
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Reactivity and Oxidizing Power:
- Fluorine (
F₂) is the most electronegative element and the strongest oxidizing agent in the periodic table. Its standard electrode potential (E° = +2.87 V forF₂/F⁻) is significantly higher than that of chlorine (E° = +1.36 V forCl₂/Cl⁻). This indicates thatF₂has a much stronger tendency to accept electrons and get reduced (i.e., oxidize other substances) compared toCl₂. F₂reacts explosively and violently with water to produce hydrofluoric acid (HF) and oxygen (O₂), or sometimes ozone (O₃), rather than forming hypofluorous acid (HOF) which is highly unstable and explosive.2F₂ (g) + 2H₂O (l) → 4HF (aq) + O₂ (g)This reaction is extremely vigorous and difficult to control. The formation ofO₂orO₃meansF₂does not primarily generate nascent oxygen needed for bleaching in a controlled manner viaHOFdecomposition like chlorine.- Chlorine (
Cl₂), on the other hand, reacts moderately with water to form hypochlorous acid (HOCl) and hydrochloric acid (HCl).Cl₂ (g) + H₂O (l) → HCl (aq) + HOCl (aq)HOClthen decomposes to produce nascent oxygen[O], which is the actual bleaching agent.HOCl → HCl + [O]This reaction is controllable, allowing for a sustained and effective bleaching action without extreme hazards.
- Fluorine (
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Control and Selectivity:
- Fluorine’s extreme reactivity makes it highly indiscriminate. It reacts with almost anything, including the substrate itself or components of the bleaching apparatus, often leading to degradation rather than selective bleaching. Its reactions are difficult to regulate, making it impractical for most industrial bleaching processes.
- Chlorine’s reactivity, while strong, is more moderate and controllable. It primarily oxidizes the chromophores (color-imparting groups) in substances without excessively degrading the material itself, especially under controlled conditions (e.g., specific pH, temperature).
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Cost and Handling:
- Fluorine is much more expensive to produce and handle safely due to its extreme reactivity and corrosive nature. Specialized, inert equipment is required, increasing operational costs.
- Chlorine is relatively cheaper to produce and its handling, though requiring precautions, is far less demanding and more manageable at industrial scales.
In summary, despite fluorine being a stronger oxidizing agent, its uncontrollable and indiscriminate reactivity with water and other materials, coupled with high cost and safety concerns, makes it unsuitable for most industrial bleaching applications. Chlorine, with its more moderate and controllable oxidizing power and ability to generate nascent oxygen efficiently in aqueous solutions, proves to be a more practical and extensively used bleaching agent.