Introduction to Flerovium
Flerovium (Fl) is a synthetic chemical element with atomic number 114. It is an extremely heavy and radioactive element, not found naturally on Earth. It was first synthesized in 1998 at the Joint Institute for Nuclear Research (JINR) in Dubna, Russia, and named after the Russian physicist Georgy Flyorov, the founder of the Flerov Laboratory of Nuclear Reactions at JINR. Due to its extremely short half-life, its chemical properties are difficult to study, but it is predicted to be a post-transition metal.
Basic Properties
Flerovium is classified as a superheavy element. All its isotopes are highly unstable and decay very quickly, making practical applications impossible. Its existence primarily contributes to the understanding of the limits of the periodic table and the stability of very heavy nuclei, including the theoretical “island of stability.”
Atomic Composition
The atomic structure of Flerovium, like all elements, is defined by the number of protons, neutrons, and electrons. For a neutral atom, the number of protons is equal to the number of electrons.
Protons, Neutrons, and Electrons
- Atomic Number (Z): The atomic number of Flerovium is 114. This means every Flerovium atom contains 114 protons in its nucleus.
- Electrons: In a neutral Flerovium atom, the number of electrons is equal to the number of protons. Therefore, a neutral Flerovium atom has 114 electrons.
- Neutrons: The number of neutrons varies among different isotopes of Flerovium. The most stable known isotope is Flerovium-289 ($^{289}$Fl). For this isotope:
- Mass Number (A) = 289
- Number of neutrons = Mass Number (A) - Atomic Number (Z) = 289 - 114 = 175 neutrons.
Electron Arrangement
The arrangement of electrons in an atom dictates its chemical behavior. For Flerovium, a superheavy element, its electron configuration is derived from the Aufbau principle, though relativistic effects are significant for such large atoms.
Electron Configuration
The electron configuration of a neutral Flerovium atom (Z=114) describes how its 114 electrons are distributed among the various energy levels and sublevels (orbitals). Using the noble gas core notation of Radon (Rn, Z=86) for simplicity, the full configuration is:
$[Rn]\ 5f^{14}\ 6d^{10}\ 7s^2\ 7p^2$
Expanding this to show all occupied shells and subshells:
$1s^2\ 2s^2\ 2p^6\ 3s^2\ 3p^6\ 4s^2\ 3d^{10}\ 4p^6\ 5s^2\ 4d^{10}\ 5p^6\ 6s^2\ 4f^{14}\ 5d^{10}\ 6p^6\ 7s^2\ 5f^{14}\ 6d^{10}\ 7p^2$
Valence Electrons
Valence electrons are the electrons located in the outermost principal energy level of an atom. These electrons are primarily involved in chemical bonding. For Flerovium, the outermost principal energy level is the 7th shell.
In the 7th shell, the occupied subshells are $7s^2$ and $7p^2$. Therefore, the number of valence electrons for Flerovium is the sum of electrons in these outermost subshells: $2 (from\ 7s) + 2 (from\ 7p) = 4$ valence electrons.
Flerovium belongs to Group 14 of the periodic table, which typically corresponds to elements having four valence electrons.